左键弹出菜单的问题[已解决]
本帖最后由 wanghong01 于 2010-11-20 02:58 编辑怎样使鼠标左键点击一个控件，也能象右键点击一样弹出菜单呢？{:face (382):} 帮助里有#include <GUIConstantsEx.au3>
#include <ButtonConstants.au3>
Local $hGui, $OptionsBtn, $OptionsDummy, $OptionsContext, $OptionsCommon, $OptionsFile, $msg
Local $OptionsExit, $HelpBtn, $HelpDummy, $HelpContext, $HelpWWW, $HelpAbout
$hGui = GUICreate("My GUI", 170, 40)
$OptionsBtn = GUICtrlCreateButton("&Options", 10, 10, 70, 20, $BS_FLAT)
; At first create a dummy control for the options and a contextmenu for it
$OptionsDummy = GUICtrlCreateDummy()
$OptionsContext = GUICtrlCreateContextMenu($OptionsDummy)
$OptionsCommon = GUICtrlCreateMenuItem("Common", $OptionsContext)
$OptionsFile = GUICtrlCreateMenuItem("File", $OptionsContext)
GUICtrlCreateMenuItem("", $OptionsContext)
$OptionsExit = GUICtrlCreateMenuItem("Exit", $OptionsContext)
$HelpBtn = GUICtrlCreateButton("&Help", 90, 10, 70, 20, $BS_FLAT)
; Create a dummy control and a contextmenu for the help too
$HelpDummy = GUICtrlCreateDummy()
$HelpContext = GUICtrlCreateContextMenu($HelpDummy)
$HelpWWW = GUICtrlCreateMenuItem("Website", $HelpContext)
GUICtrlCreateMenuItem("", $HelpContext)
$HelpAbout = GUICtrlCreateMenuItem("About...", $HelpContext)
GUISetState()
While 1
$msg = GUIGetMsg()
Switch $msg
Case $OptionsExit, $GUI_EVENT_CLOSE
ExitLoop
Case $OptionsBtn
ShowMenu($hGui, $msg, $OptionsContext)
Case $HelpBtn
ShowMenu($hGui, $msg, $HelpContext)
Case $HelpAbout
MsgBox(64, "About...", "GUICtrlGetHandle-Sample")
EndSwitch
WEnd
GUIDelete()
; Show a menu in a given GUI window which belongs to a given GUI ctrl
Func ShowMenu($hWnd, $CtrlID, $nContextID)
Local $arPos, $x, $y
Local $hMenu = GUICtrlGetHandle($nContextID)
$arPos = ControlGetPos($hWnd, "", $CtrlID)
$x = $arPos
$y = $arPos + $arPos
ClientToScreen($hWnd, $x, $y)
TrackPopupMenu($hWnd, $hMenu, $x, $y)
EndFunc ;==>ShowMenu
; Convert the client (GUI) coordinates to screen (desktop) coordinates
Func ClientToScreen($hWnd, ByRef $x, ByRef $y)
Local $stPoint = DllStructCreate("int;int")
DllStructSetData($stPoint, 1, $x)
DllStructSetData($stPoint, 2, $y)
DllCall("user32.dll", "int", "ClientToScreen", "hwnd", $hWnd, "ptr", DllStructGetPtr($stPoint))
$x = DllStructGetData($stPoint, 1)
$y = DllStructGetData($stPoint, 2)
; release Struct not really needed as it is a local
$stPoint = 0
EndFunc ;==>ClientToScreen
; Show at the given coordinates (x, y) the popup menu (hMenu) which belongs to a given GUI window (hWnd)
Func TrackPopupMenu($hWnd, $hMenu, $x, $y)
DllCall("user32.dll", "int", "TrackPopupMenuEx", "hwnd", $hMenu, "int", 0, "int", $x, "int", $y, "hwnd", $hWnd, "ptr", 0)
EndFunc ;==>TrackPopupMenu 回复 2# afan
谢谢楼上的，你真是大好人啦{:face (451):} {:face (117):} {:1_415:} 东西确实在帮助里面有，可惜讲解太少了 可惜我这里来了一个按钮上弹出菜单，就如开始菜单一样的。不知道如何实现了
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