写入注册表二进制问题
原来在注册表中，导出的注册表内容为：Windows Registry Editor Version 5.00
"License"=hex:db,89,29,18,04,5e,0f,5e,78,9c,e3,f1,54,f0,c9,2f,4b,55,70,ce,c8,\
cc,4b,94,35,34,77,b4,34,d0,75,b5,30,35,b3,d0,35,b2,8c,32,77,d6,35,b4,0c,37,\
75,d2,35,37,0b,31,b1,04,00,f6,37,0a,b7
用注册表转换工具转换为：
RegWrite('HKEY_LOCAL_MACHINE\SOFTWARE\ES-Computing\EditPlus 3\Install')
RegWrite('HKEY_LOCAL_MACHINE\SOFTWARE\ES-Computing\EditPlus 3\Install', 'License', 'REG_BINARY', 'db892918045e0f5e789ce3f154f0c92f4b5570cec8cc4b94353477b434d075b53035b3d035b28c3277d635b40c3775d235370b31b10400f6370ab7')
运行 上面AU3代码后到注册表中查看结果，跟原来的注册表内容不一样。变成了：
Windows Registry Editor Version 5.00
"License"=hex:64,62,2c,38,39,2c,32,39,2c,31,38,2c,30,34,2c,35,65,2c,30,66,2c,\
35,65,2c,37,38,2c,39,63,2c,65,33,2c,66,31,2c,35,34,2c,66,30,2c,63,39,2c,32,\
66,2c,34,62,2c,35,35,2c,37,30,2c,63,65,2c,63,38,2c,63,63,2c,34,62,2c,39,34,\
2c,33,35,2c,33,34,2c,37,37,2c,62,34,2c,33,34,2c,64,30,2c,37,35,2c,62,35,2c,\
33,30,2c,33,35,2c,62,33,2c,64,30,2c,33,35,2c,62,32,2c,38,63,2c,33,32,2c,37,\
37,2c,64,36,2c,33,35,2c,62,34,2c,30,63,2c,33,37,2c,37,35,2c,64,32,2c,33,35,\
2c,33,37,2c,30,62,2c,33,31,2c,62,31,2c,30,34,2c,30,30,2c,66,36,2c,33,37,2c,\
30,61,2c,62,37
这是为何原因？！ 解决了。。。原来 需要在 db892918045e0f5e789ce3前面加上0x （零X）就可以了。 新手路过，先标记一下 回复 3# yejier1983
新手，说一句，二进制在注册表里是以16进制表达的，当然，你完全可以用0和1去写，不过累了点
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