论坛 › 已解决问题区 › （已解决）listview函数，删除列可以，删除行不行。是不是我英语太差理解错了？

330259789 发表于 2010-12-19 21:01:01

（已解决）listview函数，删除列可以，删除行不行。是不是我英语太差理解错了？

本帖最后由 330259789 于 2010-12-21 18:43 编辑

如题
#include <ButtonConstants.au3>
#include <GUIConstantsEx.au3>
#include <ListViewConstants.au3>
#include <WindowsConstants.au3>
#include <GUIConstantsEx.au3>
#include <GuiListView.au3>
#Region ### START Koda GUI section ### Form=
Opt("GUIOnEventMode", 1)
$Form1 = GUICreate("Form1", 623, 442, 192, 124)
GUISetOnEvent($GUI_EVENT_CLOSE, "Close")
$Button1 = GUICtrlCreateButton("Button1", 0, 0, 75, 25)
GUICtrlSetOnEvent(-1, "del")
$ListView1 = GUICtrlCreateListView("|||", 0, 20, 590, 224)
_GUICtrlListView_AddItem($ListView1, "")
_GUICtrlListView_AddItem($ListView1, "")
_GUICtrlListView_AddItem($ListView1, "")
GUISetState(@SW_SHOW)
#EndRegion ### END Koda GUI section ###
_GUICtrlListView_SetItemText($ListView1, 0, 123, 0)
        _GUICtrlListView_SetItemText($ListView1,1, 123, 0)
        _GUICtrlListView_SetItemText($ListView1, 2, 12312, 0)
        _GUICtrlListView_SetItemText($ListView1, 3, 123, 0)
        _GUICtrlListView_SetItemText($ListView1, 0, 341234, 1)
        _GUICtrlListView_SetItemText($ListView1, 1, 324124, 1)
        _GUICtrlListView_SetItemText($ListView1, 2, 12341234, 1)
        _GUICtrlListView_SetItemText($ListView1, 3, 2341235, 1)
        _GUICtrlListView_SetItemText($ListView1, 0, 23412341, 2)
        _GUICtrlListView_SetItemText($ListView1,1, 231412351235, 2)
While 1

WEnd
Func del()
                If _GUICtrlListView_DeleteColumn($ListView1,1) Then
                MsgBox(0,0,"删除列成功")
        Else
                MsgBox(0,0,"删除列失败")
                EndIf
        If _GUICtrlListView_DeleteItem($ListView1,0) Then
                MsgBox(0,0,"删除行成功")
        Else
                MsgBox(0,0,"删除行失败")
                EndIf
EndFunc   ;==>del


Func Close()
        Exit
EndFunc   ;==>Close

298311657 发表于 2010-12-19 21:26:48

#include <ButtonConstants.au3>
#include <GUIConstantsEx.au3>
#include <ListViewConstants.au3>
#include <WindowsConstants.au3>
#include <GUIConstantsEx.au3>
#include <GuiListView.au3>

Opt("GUIOnEventMode", 1)
$Form1 = GUICreate("Form1", 805, 305, 192, 124)
GUISetOnEvent($GUI_EVENT_CLOSE, "Close")

$Button1 = GUICtrlCreateButton("del1", 2, 2, 75, 25)
GUICtrlSetOnEvent(-1, "del1")

$ListView1 = _GUICtrlListView_Create($Form1, "col1|col2|col3", 2, 30, 394, 268)
Dim $aItems
For $iI = 0 To UBound($aItems) - 1
        $aItems[$iI] = "Item " & $iI
        $aItems[$iI] = "Item " & $iI & "-1"
        $aItems[$iI] = "Item " & $iI & "-2"
Next
_GUICtrlListView_AddArray($ListView1, $aItems)

$Button1 = GUICtrlCreateButton("del2", 400, 2, 75, 25)
GUICtrlSetOnEvent(-1, "del2")

$ListView2 = GUICtrlCreateListView("col1|col2|col3", 402, 30, 394, 268)
For $iI = 0 To 9
        GUICtrlCreateListViewItem("Item " & $iI & "|Item " & $iI & "-1|Item " & $iI & "-2", $ListView2)
Next

GUISetState(@SW_SHOW)

While 1
        Sleep(10000)
WEnd

Func del1()
        MsgBox(0,"","ListView1删除列:"&_GUICtrlListView_DeleteColumn($ListView1,1))
        MsgBox(0,"","ListView1删除行:"&_GUICtrlListView_DeleteItem($ListView1,1))
EndFunc   ;==>del

Func del2()
        MsgBox(0,"","ListView2删除列:"&_GUICtrlListView_DeleteColumn($ListView2,1))
        MsgBox(0,"","ListView2删除行:"&_GUICtrlListView_DeleteItem($ListView2,1))
EndFunc   ;==>del

Func Close()
        Exit
EndFunc   ;==>Close

yhxhappy 发表于 2010-12-19 21:30:59

_GUICtrlListView_DeleteItem 是删除行
_GUICtrlListView_DeleteColumn 是删除列

330259789 发表于 2010-12-19 21:56:21

回复 2# 298311657

你的是可以的，可是为什么我的代码就是不行啊？
我用的也是_GUICtrlListView_DeleteItem啊

330259789 发表于 2010-12-19 21:57:17

回复 3# yhxhappy

函数我写的应该没错吧？可是为什么删除不了呢？

yhxhappy 发表于 2010-12-19 23:20:59

_GUICtrlListView_DeleteItem(GUICtrlGetHandle($ListView1), 1)

330259789 发表于 2010-12-21 18:43:19

回复 6# yhxhappy


果然可以，谢啦

syhw222 发表于 2010-12-25 13:15:21

学习，学习！

hollandmfq 发表于 2014-5-6 08:13:37

雷锋精神传天下！谢谢分享！

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