我有个地方要延迟几个小时再往下执行,可执行没法关,怎么跳出延迟?
比如输入时间,想停止运行重新输入后执行.#include <GUIConstants.au3>
GUICreate("延迟时间", 300, 170)
GUISetState(@SW_SHOW)
GUICtrlCreateLabel("时间延迟:", 35,65)
$wait1=GUICtrlCreateInput("3",150,60,38,20)
GUICtrlCreateLabel("小时", 190,65)
$okbutton=GUICtrlCreateButton("OK", 120, 120, 60)
While 1
$Msg=GUIGetMsg()
Switch $Msg
Case $GUI_EVENT_CLOSE
Exit
Case $okbutton
$w=GUICtrlRead($wait1)*60*60*1000
Sleep($w)
EndSwitch
WEnd
也许弱智,但请告知.
还有,如有两个条件,选一个或两个,再分别执行,怎么弄?#include <GUIConstants.au3>
GUICreate("延迟时间", 300, 170)
GUISetState(@SW_SHOW)
GUICtrlCreateLabel("时间延迟:", 35,65)
$wait1=GUICtrlCreateInput("3",150,60,38,20)
GUICtrlCreateLabel("小时", 190,65)
$okbutton=GUICtrlCreateButton("OK", 120, 120, 60)
$Label = GUICtrlCreateLabel('核弹爆炸倒计时：____秒', 65,90,200,20)
Local $bg = 0, $C = 0
While 1
$Msg=GUIGetMsg()
Switch $Msg
Case $GUI_EVENT_CLOSE
Exit
Case $okbutton
$w=GUICtrlRead($wait1)*60*60
$T1 = TimerInit()
$bg = 1
EndSwitch
If $bg = 1 Then
$T2 = Int(TimerDiff($T1) / 1000)
If $T2 >= $w Then ExitLoop
If $T2 > $C Then
$C = $T2
GUICtrlSetData($Label , '核弹爆炸倒计时： ' & $w - $T2 & ' 秒')
EndIf
EndIf
WEnd
原帖由 gxd1112 于 2008-10-19 13:28 发表 http://www.autoitx.com/images/common/back.gif
还有,如有两个条件,选一个或两个,再分别执行,怎么弄?
看说明的条件判断语句！
如果不去看可以学到东西的帮助，而只是不停的问，那不是其它问题，是懒惰．．． 用ＨＯＴＫＥＹ的退出办法：
#include <GUIConstants.au3>
GUICreate("延迟时间", 300, 170)
GUISetState(@SW_SHOW)
GUICtrlCreateLabel("时间延迟:", 35,65)
$wait1=GUICtrlCreateInput("3",150,60,38,20)
GUICtrlCreateLabel("小时", 190,65)
$okbutton=GUICtrlCreateButton("OK", 120, 120, 60)
HotKeySet('^{F7}', 'QuitQuitQuit')
While 1
$Msg=GUIGetMsg()
Switch $Msg
Case $GUI_EVENT_CLOSE
Exit
Case $okbutton
$w=GUICtrlRead($wait1)*60*60*1000
Sleep($w)
EndSwitch
WEnd
Func QuitQuitQuit()
Exit
EndFunc
谢谢!
万分感谢!总算能编下去了 学习了，谢谢分享
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